Resolved In bat file, need to parse date

In XP want to use bat file to get 2 digit year from %date% as variables for mm, dd, yy.
Is there a way to trim the 4 digit year to 2 digits?

 

I want to use something like the following:
for /f "tokens=2-4 delims=/ " %%i in ('date/t') do (
(set MM=%%i)
(set DD=%%j)
(set Yr=%%k)
)
The variable Yr is returned as 4 digits. I would like to reduce the year to 2 digits. I haven't tried basic commands ( right(%Yr%,2) )because I didn't think that would work in a bat file.
Any ideas on how to trim the variable?

 

I was able to find the requested information.

It is fairly simple, see below:

SET MM=%date:~4,2%
SET DD=%date:~7,2%
SET YY=%date:~12,2%

Thanks.