How to write a drive-independent file path

I am trying to write a small dos .bat file which I want to copy on to a CD for the ease of copying files from the CD to a hard drive.
But, not all CD drives are D:\ drives, they may as well be E:\ or F:\ or G:\
Now, what should a command line in DOS look like if I want to write it for ANY drive.
e.g "copy D:\files\*.* c:\games\" were "D" could be anything from A-Z

Thanks

 

Arie is most probably correct on this one.

"When an executable file is named on the command line (or in a batch file) without an explicit path, Dos will always first search for this file in the current directory on the current drive. If the file is not found there, Dos will then search any paths listed in the Path environmental variable. "
(Old Testament, DOS, Chapter 5, Verse 25)

So if you first select the CD ROM drive and then start the .bat, it should
run OK.
At the start of the .bat maybe add a line
PATH ;
... but not sure what Path/s re-set when .bat finishes ...
Note that you MUST first click the CD ROM drive to open it eg you cannot
run the .bat from a Windows RUN prompt.
regards

 

hello,

I believe you can do this using a Autorun.inf file. You may need to copy at the root directory of your CD XCOPY.EXE and XCOPY32.MOD from C:\Windows\Command just to be on the safe side and make sure that xcopy.exe will run even on a XP machine.
You suppose to make a BAT file also :
xcopy [source path on CD] c:\[target directory path]
and save it as, e.g A.BAT
To make the Autorun.inf, open a new text document and type there:

[AutoRun]
open=A.BAT

and save it as AUTORUN.INF

I've tried all these using a virtual CD and it worked. It's better to try it with
a CD-RW - that' the real thing, of course.

good luck and let us know how it worked

Stefan